Vector \vec{A} has magnitude 12.0 m, and vector \vec{B} has magnitud

Dillard

Dillard

Answered question

2021-09-26

Vector A has magnitude 12.0 m, and vector B has magnitude 16.0 m. The scalar product AB is 112.0 m2. What is the magnitude of the vector product between these two vectors?

Answer & Explanation

cyhuddwyr9

cyhuddwyr9

Skilled2021-09-27Added 90 answers

AB=112 m2
To find the angle between A and B, we will use the scalar product equation.
AB=ABcosϕ
112=(12)(16)cosϕ
cosϕ=112(12)(16)
ϕ=cos1(112(12)(16))
=54.3
To calculate the magnitude of the vector product, use the following equation:
C=ABsinϕ
C=(12)(16)sin54.3
=156 m2
Result: C=156 m2

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