Find an explicit description off Nul A by listing vectors that span the null spa

Lewis Harvey

Lewis Harvey

Answered question

2021-11-05

Find an explicit description off Nul A by listing vectors that span the null space.
A=[13500142]

Answer & Explanation

Anonym

Anonym

Skilled2021-11-06Added 108 answers

Step 1
First find the general solution of Ax=0 in terms of the free variables. Since
[A0]=[1350001420]R1R13R2~[1076001420]
The general solution is x1=7x36x4, x2=4x3+2x4,with and x4 free.
So
x=[x1x2x3x4]=x3[7410]+x4[6201]
and a spanning set for Nul A is
{[7410],[6201]}

yunitsiL

yunitsiL

Skilled2021-11-10Added 108 answers

Step 1
The reduced row echelon form of the matrix is [10760142] (for steps, see rref calculator).
To find the null space, solve the matrix equation [10760142][x1x2x3x4]=[00]
If we take x3=t, x4=s, then x1=6s+7t, x2=2s4t
Thus, x=[6s+7t2s4tts]=[7410]t+[6201]s
This is the null space.
The nullity of a matrix is the dimension of the basis for the null space.
Thus, the nullity of the matrix is 2.
The basis for the null space is Undefined control sequence \bmatrix
The nullity of the matrix is 2A.

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