how to find Form a quadratic equation that passes through the following points:

Answered question

2021-12-09

how to find Form a quadratic equation that passes through the following points:
 

 

  1. (0, 0), (2, 0) and (-1, 3)       
  2. (3, 0), (– 4, 0) and (0, –12)

Answer & Explanation

star233

star233

Skilled2023-04-21Added 403 answers

To form a quadratic equation that passes through the given points, we can use the general form of a quadratic equation:

y=ax2+bx+c

where a, b, and c are constants.

To find these constants, we substitute the given points in the equation to form a system of equations.

For the first set of points:

(0, 0): 0=a(0)2+b(0)+cc=0
(2, 0): 0=a(2)2+b(2)+04a+2b=0
(-1, 3): 3=a(-1)2+b(-1)+0a-b=-3

Now, we can solve this system of equations to find the values of a and b.

From equation 1, c = 0. 
Adding equations 2 and 3, we get:

4a+2b+a-b=0-35a+b=-3

Substituting b=-5a-3 in equation 2, we get:

0=a(2)2+(-5a-3)(2)+0a=1

Substituting a = 1 in b = -5a - 3, we get b = -8.

Therefore, the quadratic equation that passes through the points (0, 0), (2, 0), and (-1, 3) is:

y=x2-8x

For the second set of points:

(3, 0): 0=a(3)2+b(3)+c9a+3b+c=0
(-4, 0): 0=a(-4)2+b(-4)+c16a-4b+c=0
(0, -12): -12=a(0)2+b(0)+cc=-12

Substituting c=-12 in equations 1 and 2, we get:

9a+3b=12 
16a-4b=12

Solving this system of equations, we get a=-316 and b=94.

Therefore, the quadratic equation that passes through the points (3, 0), (–4, 0), and (0, –12) is:

y=-316x2+94x-12

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