In the vectorspace <mi mathvariant="double-struck">R 2 </msup> two vectors are

lifretatox8n

lifretatox8n

Answered question

2022-05-12

In the vectorspace R 2 two vectors are given (Which also form the basis a): a 1 = ( 8 , 3 ) and a 2 = ( 5 , 2 )
A linear mapping is determined by: f ( a 1 ) = 2 a 1 4 a 2 and f ( a 2 ) = a 1 + 2 a 2
How can one determine the transformation matrix of f with respect to the standard e-basis?

Answer & Explanation

radcas87gex5r

radcas87gex5r

Beginner2022-05-13Added 13 answers

Given a linear map T : V W suppose A = { a 1 , . . . , a n } is a basis for V and B = { b 1 , . . . , b m } is a basis for W i.e they are finite dimensional vector spaces. We will write T = ( T ( a 1 ) T ( a n ) ) .
Given a vector v , you would like to find [ T v ] B . First we have v = k v k a k which we identify with ( v 1 , . . . , v n ) T := [ v ] A i.e its coordinates representation. And now, by the definition of matrix multiplication,
T v = j = 1 n T ( a j )   v j = ( T ( a 1 ) T ( a n ) ) ( v 1 v n ) [ T v ] B = j = 1 n [ T ( a j ) ] B   v j = ( [ T ( a 1 ) ] B [ T ( a n ) ] B ) := T B A [ v ] A
Therefore, given the linear map f : ( R 2 , { a 1 , a 2 } := A ) ( R 2 , { ( 1 , 0 ) T , ( 0 , 1 ) T } := B ), we have that the coordinate transformation matrix is given by,
f B A = ( [ f ( a 1 ) ] B [ f ( a 2 ) ] B )
i.e we have to write f ( a 1 ) = 2 a 1 4 a 2 and f ( a 2 ) = a 1 + 2 a 2 in terms of the unit basis vectors ( 1 , 0 ) T and ( 0 , 1 ) T . Given a 1 = ( 8 , 3 ) T , a 2 = ( 5 , 2 ) T then f ( a 1 ) = ( 4 , 2 ) T and f ( a 2 ) = ( 2 , 1 ) T . It follows that the matrix is,
f B A = ( ( 4 2 ) ( 2 1 ) )
If you want the transformation matrix with respect to basis A then you are trying to compute f A A . It follows that f A A = I A B f B A where,
I A B = ( 2 5 3 8 )
i.e we have,
f A A = ( 2 1 4 2 )

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