Does there exist a matrix A for which A M = M T </msup> for every M . Th

Liberty Mack

Liberty Mack

Answered question

2022-05-20

Does there exist a matrix A for which A M = M T for every M. The answer to this is obviously no as I can vary the dimension of M. But now this lead me to think , if I take , lets say only 2 × 2 matrix into consideration. Now for a matrix M, A = M T M 1 so A is not fixed and depends on M, but the operation follows all conditions of a linear transformation and I had read that any linear transformation can be represented as a matrix. So is the last statement wrong or my argument flawed?

Answer & Explanation

Jarrett Reyes

Jarrett Reyes

Beginner2022-05-21Added 8 answers

The operation that transposes "all" matrices is, itself, not a linear transformation, because linear transformations are only defined on vector spaces.Also, I do not understand what the matrix A = M T M 1 is supposed to be, especially since M need not be invertible. Your understanding here seems to be lacking...
However:
The operation T n : R n × n R n × n , defined by T n : A A T is a linear transformation. However, it is an operation that maps a n 2 dimensional space into itself, meaning that the matrix representing it will have n 2 columns and n 2 rows!
Jerry Villegas

Jerry Villegas

Beginner2022-05-22Added 4 answers

The vector space of n × n matrices is n 2 -dimensional, hence the matrix representation of the (indeed) linear map X X T would have to be n 2 × n 2 (and you better rearrange/interprete the given n × n matrices into n 2 × 1 column vectors).

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