Finding inverse matrix A &#x2212;<!-- - --> 1 </mrow> </msup>

hornejada1c

hornejada1c

Answered question

2022-07-01

Finding inverse matrix A 1 and I was given hint that I could firstly find inverse matrix to matrix B which is transformed from A.
A = ( 1 3 9 27 3 3 9 27 9 9 9 27 27 27 27 27 )
B = ( 1 3 9 27 1 1 3 9 1 1 1 3 1 1 1 1 )
I found that that B 1 is
B 1 = ( 1 2 3 2 0 0 1 2 2 3 2 0 0 1 2 2 3 2 0 0 1 2 1 2 )
I don't know how to continue. What rule do I use to find A 1 ?

Answer & Explanation

earendil666h1

earendil666h1

Beginner2022-07-02Added 10 answers

Note that A = ( 1 0 0 0 0 3 0 0 0 0 9 0 0 0 0 27 ) B.
Hence, A 1 = B 1 ( 1 0 0 0 0 1 / 3 0 0 0 0 1 / 9 0 0 0 0 1 / 27 )
kolutastmr

kolutastmr

Beginner2022-07-03Added 2 answers

Thanks, I solved it correctly according to solution in my textbook :)

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