a5=0 and a15=4 what is the sum of

Usman Zahid

Usman Zahid

Answered question

2022-07-24

a5=0 and a15=4 what is the sum of the first 15 terms of that arithmetic sequence

Answer & Explanation

karton

karton

Expert2023-06-02Added 613 answers

We are given an arithmetic sequence with the first term a5=0 and the fifteenth term a15=4. We need to find the sum of the first 15 terms of this sequence.
The general formula for the nth term of an arithmetic sequence is given by:
an=a1+(n1)d,
where a1 is the first term and d is the common difference.
We are given that a5=0, so we can substitute these values into the formula:
0=a1+(51)d.
Simplifying this equation, we have:
0=a1+4d.
Similarly, we are given that a15=4, so we can substitute these values into the formula:
4=a1+(151)d.
Simplifying this equation, we have:
4=a1+14d.
We now have a system of two equations with two variables (a1 and d):
{a1+4d=0a1+14d=4.
To solve this system, we can subtract the first equation from the second equation:
(a1+14d)(a1+4d)=40,
14d4d=4,
10d=4,
d=410,
d=25.
Substituting this value of d back into the first equation, we can solve for a1:
a1+4(25)=0,
a1+85=0,
a1=85.
Now that we have determined the first term a1=85 and the common difference d=25, we can find the sum of the first 15 terms of the arithmetic sequence using the formula for the sum of an arithmetic series:
S15=n2(a1+an),
where n is the number of terms.
Substituting the values, we get:
S15=152(85+a15),
S15=152(85+4),
S15=152(85+205),
S15=152(125),
S15=152·125,
S15=3·12,
S15=36.
Therefore, the sum of the first 15 terms of the arithmetic sequence is 36.

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