proximumha
2022-08-05
Andres Barrett
Beginner2022-08-06Added 14 answers
parallel to b means vector =ab for some constant a
u orthogonal to b meansu.b = 0
We need u + ab = (4,-2,6)(i)
u.b = 0 means -2ui + uj -3uk = 0 (ii)
From (i):
(ui,uj,uk) + (4a, -2a,6a) = (4,-2,6)
ui + 4a = 4
uj - 2a = -2
uk +6a = 6
eliminate the u's from (ii) to get an equation in a:
-2(4-4a) + (2a -2) -3(6-6a)=0
-8+8a+2a-2-18+18a=0
28a = -28
a = -1
So
ui = 8
uj = -4
uk = 12
So the parallel vector is:
(2,-1,3)
An orthogonal vector is:
(8,-4,12)
In order to give the correctlength, we must scale the orthogonal vector. Therefore:
(2,-1,3) + b(8,-4,12) = (4,-2,6)
where b is the scale factor
This is satisfied for b=1/4
The 2 vectors are as follows:
(2,-1,3) and (2,-1,3)
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