A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 121.1-cm and a standard deviation of 2.2-cm. For shipment, 26 steel rods are bundled together.
Find P91, which is the average length separating the smallest 91% bundles from the largest 9% bundles.
P91 = -cm
Enter your answer as a number accurate to 2 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
A population of values has a normal distribution with and . You intend to draw a random sample of size .
Find the probability that a single randomly selected value is between 119.8 and 121.2.
P(119.8 < X < 121.2)
Find the probability that a sample of size is randomly selected with a mean between 119.8 and 121.2.
P(119.8 < M < 121.2)
Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Finding upper confidence limit without mean and sd
So the question I'm trying to answer looks like this:
We are interested in p, the population proportion of all people who are currently happy with their cell phone plans. In a small study done in 2012, it was found that in a sample of 150 people, there were 90 who were happy with their cell phone plans.
Find the upper confidence limit of an 82% confidence interval for p.
I know the formula is
In a family of 6, what is the probability of getting 1 boy and 5 girls