How to identify cot^2x(sin^2x)?

Kason Murray

Kason Murray

Answered question

2022-12-30

How to identify cot2x(sin2x)?

Answer & Explanation

Jaqueline Byrd

Jaqueline Byrd

Beginner2022-12-31Added 4 answers

Undefined control sequence \cancel
Kymani Estrada

Kymani Estrada

Beginner2023-01-01Added 2 answers

I take it you mean \(\displaystyle{\color{blue}\text{}}\sim{p}{l}{\quad\text{if}\quad}{y}\text{}\)
Using the \(\displaystyle{\color{blue}\text{}}{t}{r}{i}{g}{o}{n}{o}{m}{e}{t}{r}{i}{c}{i}{d}{e}{n}{t}{i}{t}{y}\text{}\)
\(\displaystyle{\color{red}{\overline{{\underline{{{\left|{\color{white}{\frac{{2}}{{2}}}}{\color{black}{{{\cot}^{{2}}{x}}=\frac{{{{\cos}^{{2}}{x}}}}{{{{\sin}^{{2}}{x}}}}}}{\color{white}{\frac{{2}}{{2}}}}\right|}}}}}}}\)
\(\displaystyle\Rightarrow{{\cot}^{{2}}{x}}{\left({{\sin}^{{2}}{x}}\right)}\)
\(\displaystyle=\frac{{{\cos}^{{2}}{x}}}{\cancel{{{{\sin}^{{2}}{x}}}}^{{1}}}\times\cancel{{{{\sin}^{{2}}{x}}}}^{{1}}\)
\(\displaystyle={{\cos}^{{2}}{x}}\)

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