Resolved: "How to simplify sin⁡80∘−sin⁡10∘sin⁡80∘+sin⁡10∘?"

Deven Blanchard

Answered question

2023-01-20

How to simplify

\frac{{\sin 80}^{\circ} - {\sin 10}^{\circ}}{{\sin 80}^{\circ} + {\sin 10}^{\circ}}

zupreisen14v

Beginner2023-01-21Added 11 answers

\sin a \pm \sin b = 2 \sin (\frac{a \pm b}{2}) \cos (\frac{a \mp b}{2})

\tan A = \frac{\sin A}{\cos A}

\frac{{\sin 80}^{\circ} - {\sin 10}^{\circ}}{{\sin 80}^{\circ} + {\sin 10}^{\circ}} = \frac{{\sin 35}^{\circ} {\cos 45}^{\circ}}{{\sin 45}^{\circ} {\cos 35}^{\circ}} = \frac{{\tan 35}^{\circ}}{{\tan 45}^{\circ}} = {\tan 35}^{\circ}

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