"How to simplify sin⁡((π2)+h)−sin⁡(π2)h?" was answered by our experts

animeagan0o8

Answered question

2023-01-21

How to simplify

\frac{\sin ((\frac{π}{2}) + h) - \sin (\frac{π}{2})}{h}

Londyn Garcia

Beginner2023-01-22Added 7 answers

\frac{\sin ((\frac{π}{2}) + h) - \sin (\frac{π}{2})}{h} = \frac{(\sin (\frac{π}{2}) cosh + \cos (\frac{π}{2}) \cdot sinh) - \sin (\frac{π}{2})}{h} = \frac{cosh - 1}{h}

Note that
1.

\sin (a + b) = \sin a \cdot \cos b + \cos a \cdot \sin b

\sin (\frac{π}{2}) = 1

\cos (\frac{π}{2}) = 0

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