If sin of theta equals 3/8 and theta is in quadrant II. what are cos, tan, csc, cot, and sec of theta?

Maribel Ali

Maribel Ali

Answered question

2023-03-05

If sin of theta equals 3/8 and theta is in quadrant II. what are cos, tan, csc, cot, and sec of theta?

Answer & Explanation

kizintefevd3

kizintefevd3

Beginner2023-03-06Added 4 answers

sin θ = 3 8
By rearranging the Pythagorean theorem, we can calculate the adjacent side, b, since we already have the side opposite to θ , 3 , and the hypotenuse, 8 .
a 2 + b 2 = c 2
b 2 = c 2 - a 2
b 2 = 8 2 - 3 2
b 2 = 64 - 9
b 2 = 55
b = - 55
From this, we can determine that the side that is next to it has a length of - 55 units, since the x-axis is negative in the second quadrant. Therefore, we can infer that cos θ = - 55 8 and tan θ = - 3 55
Now, using the reciprocal identities, we must take the reciprocals of forces, sine, and cosine.
csc θ = 1 sin θ
sec θ = 1 cos θ
cot θ = 1 tan θ
So,
csc θ = 8 3 , sec θ = - 8 55 and cot θ = - 55 3
In conclusion, the six trigonometric ratios are:
sin θ = 3 8
cos θ = - 55 8
tan θ = - 3 55
csc θ = 8 3
sec θ = - 8 55
cot θ = - 55 3
Nhluvukoj6m

Nhluvukoj6m

Beginner2023-03-07Added 6 answers

sin θ = 3 8 ( 1 )
csc θ = 1 sin θ = 8 3 ( 2 )
cos θ = ± 1 - sin 2 θ
× × x = - 1 - 9 64
× × x = - 55 64
cos θ = - 55 8 ( 3 )
sec θ = 1 cos θ = - 8 55 ( 4 )
sec θ = 1 cos θ = - 8 55 ( 4 )
tan θ = sin θ cos θ
× × = 3 8 × - 8 55 = - 3 55 ( 5 )
cot θ = 1 tan θ = - 55 3 ( 6 )

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