Alfred Elliott

2023-03-19

The sides of certain triangles are given below. Determine which of them are right triangies. (i) a = 7cm, b=24 an and c=25cm (ii) a =9 cm, b= 16cm and c = 18 cm (iii) a=1.6 cm, b=3.8 cm and c=4 cm (iv) a =8 cm, b = 10cm and c = 6 cm

Haylee French

Beginner2023-03-20Added 7 answers

Explanation:

1)

${c}^{2}={25}^{2}=625$

${a}^{2}+{b}^{2}={7}^{2}+{24}^{2}$

=49+576=625

Since ${c}^{2}={a}^{2}+{b}^{2}$

(right triangle)

2)

${c}^{2}={18}^{2}=324$

${a}^{2}+{b}^{2}={9}^{2}+{16}^{2}$

=81+256=337

Since ${c}^{2}\ne {a}^{2}+{b}^{2}$

(not right triangle)

3)

${c}^{2}={4}^{2}=16$

${a}^{2}+{b}^{2}={3.8}^{2}+{1.6}^{2}$

=14.44+2.56=17

Since

${c}^{2}\ne {a}^{2}+{b}^{2}$

(not right triangle)

4)

${c}^{2}={10}^{2}=100$

${a}^{2}+{b}^{2}={8}^{2}+{6}^{2}$

=64+36=100

Since

${c}^{2}={a}^{2}+{b}^{2}$

(right triangle)

1)

${c}^{2}={25}^{2}=625$

${a}^{2}+{b}^{2}={7}^{2}+{24}^{2}$

=49+576=625

Since ${c}^{2}={a}^{2}+{b}^{2}$

(right triangle)

2)

${c}^{2}={18}^{2}=324$

${a}^{2}+{b}^{2}={9}^{2}+{16}^{2}$

=81+256=337

Since ${c}^{2}\ne {a}^{2}+{b}^{2}$

(not right triangle)

3)

${c}^{2}={4}^{2}=16$

${a}^{2}+{b}^{2}={3.8}^{2}+{1.6}^{2}$

=14.44+2.56=17

Since

${c}^{2}\ne {a}^{2}+{b}^{2}$

(not right triangle)

4)

${c}^{2}={10}^{2}=100$

${a}^{2}+{b}^{2}={8}^{2}+{6}^{2}$

=64+36=100

Since

${c}^{2}={a}^{2}+{b}^{2}$

(right triangle)

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