facas9

2020-11-07

In quadrant I, drawn a right triangle with one leg on the x-axis and its hypotenuse on the terminal side of drawn in standard position. If

Malena

Skilled2020-11-08Added 83 answers

Let opp = 7 and hyp = 25.

Solve for adj (adjacent side) (Pythagorean Theorem):

$op{p}^{2}+ad{j}^{2}=hy{p}^{2}$

${7}^{2}+adj={25}^{2}$

$49+ad{j}^{2}=625$

$ad{j}^{2}=576$

$adj=24$

tan theta is positive:

$\mathrm{tan}\theta =\frac{opp}{adj}=\frac{7}{24}$

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