In general, tan⁡(α+β) is not equal to tan⁡α+tan⁡β. However, there are some values of α and β for which they are equal. Find such α and β and do the same for tan⁡(α−β)

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curwyrm · Accepted Answer

Let β=0° so that:  tan⁡(α+0∘)=tan⁡α+tan⁡0∘  tan⁡α=tan⁡α  Hence,  tan⁡(α+β)=tan⁡α+tan⁡β  for any value of αα given that β=0∘  A possible answer is when:  α=30∘ and β=0∘  Do the same for tan⁡(α−β). Let β=0∘ so that:  tan⁡(α−0∘)=tan⁡α−tan⁡0∘  tan⁡α=tan⁡α  Hence, tan⁡(α−β)=tan⁡α−tan⁡β for any value of αα given that β=0∘. A possible answer is when:  α=45∘ and β=0∘

Jeffrey Jordon · Accepted Answer

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In general, tan (α + β) is not equal to tan α + tan β. However, there are some values of α and β for which they are equal. Find such α and β, and do t

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