[Graph] Solving Multl-Step Equations (continued)

Question

Demi-Leigh Barrera · Accepted Answer

Using the upper left corner, t=90
The upper left triangle is a right isosceles (45-45-90) triangle so: x=45
We have an equilateral triangle having all angles n: n=60
Using Angle Addition Postulate on the upper center of the figure, x+n+p= 180
45+60+p = 180
p=75
Using Triangle Sum Theorem on the lower left triangle, p+p+m= 180
75+75+m = 180
m=30
Using the lower left corner, p+s=90
75+s=90
s=15
Using Triangle Sum Theorem on the right-hand triangle, (t+5)+n+w= 180
(90+5)+60+w = 180
w=25
Using the upper right corner, f+w=9
f+25=90
f=65
Using Triangle Sum Theorem on the p — f — y triangle, p+f+y=180
75+65+y = 180
y=40
Using Triangle Sum Theorem on the bottom triangle, k+s+m=180
k+15+30=180
k=135

[Graph] Solving Multl-Step Equations (continued)

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