cos⁡θ=913 sin⁡θ&lt;0 1. sin⁡θ=? 2. tan⁡θ=? 3. csc⁡θ=? 4. sec⁡θ=? 5. cot⁡θ=?

cos⁡θ=adjhyp=913 (opp)2=132−92 =169−81 =88 opp=±222 Since θ is in Quadrant IV, opp is −222 1. sin⁡θ=−22213 2. tan⁡θ=−2229 3. csc⁡θ=13−222 =−132244 4. sec⁡θ=139 5. cot⁡θ=9−222=−92244

Explained: "cos⁡θ=913 sin⁡θ<0 1. sin⁡θ=? 2. tan⁡θ=? 3. csc⁡θ=?..."

High School
Geometry
Trigonometry
Right triangles and trigonometry

Cabiolab

Answered question

2021-09-14

$\cos θ = \frac{9}{13}$
$\sin θ < 0$
1. $\sin θ = ?$
2. $\tan θ = ?$
3. $\csc θ = ?$
4. $\sec θ = ?$
5. $\cot θ = ?$

Answer & Explanation

tabuordg

Skilled2021-09-15Added 99 answers

$\cos θ = \frac{a d j}{h y p} = \frac{9}{13}$
${(o p p)}^{2} = 13^{2} - 9^{2}$
$= 169 - 81$
$= 88$
$o p p = \pm 2 \sqrt{22}$
Since $θ$ is in Quadrant IV, opp is $- 2 \sqrt{22}$
1. $\sin θ = \frac{- 2 \sqrt{22}}{13}$
2. $\tan θ = \frac{- 2 \sqrt{22}}{9}$
3. $\csc θ = \frac{13}{- 2 \sqrt{22}}$
$= \frac{- 13 \sqrt{22}}{44}$
4. $\sec θ = \frac{13}{9}$
5. $\cot θ = \frac{9}{- 2 \sqrt{22}} = \frac{- 9 \sqrt{22}}{44}$

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