sec2x-1=0 [0, 2pi) solve for x

Trent Carpenter

Trent Carpenter

Answered question

2021-09-14

sec2x1=0[0,2π)
solve for x

Answer & Explanation

Demi-Leigh Barrera

Demi-Leigh Barrera

Skilled2021-09-15Added 97 answers

(1cos2x)1=0
(1cos2x)(cos2xcos2x)=0
1cos2xcos2x=0
1cos2x=0
1((cosx)2(sinx)2)=0
1(cosx)2+(sinx)2=0
(sinx)2+(sinx)2=0
2(sinx)2=0
(sinx)2=0
sinx=0
x=0 or x=π

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