1/(sec theta-tan theta)+1/(sec theta+tan theta)

hexacordoK

hexacordoK

Answered question

2021-09-29

1/(secθtanθ)+1/(secθ+tanθ)

Answer & Explanation

Alara Mccarthy

Alara Mccarthy

Skilled2021-09-30Added 85 answers

We are given: \(\displaystyle\frac{{1}}{{{\sec{

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