Paligutanhk

2022-01-03

How do you solve $5{\mathrm{sin}}^{2}\left(x\right)+8\mathrm{sin}x\mathrm{cos}x-3=0$ ?

I have tried using compound angle, sum to product, pythag identities but nothing seems to work. I tried turning it into$\mathrm{sin}2x$ but then I have ${\mathrm{sin}}^{2}x$ and $\mathrm{sin}2x$ together.

I have tried using compound angle, sum to product, pythag identities but nothing seems to work. I tried turning it into

alexandrebaud43

Beginner2022-01-04Added 36 answers

Hint:

$\frac{5{\mathrm{sin}}^{2}x}{{\mathrm{cos}}^{2}x}+\frac{8\mathrm{sin}x}{\mathrm{cos}x}-\frac{3{\mathrm{sin}}^{2}x+3{\mathrm{cos}}^{2}x}{{\mathrm{cos}}^{2}x}=0$

$2{\mathrm{tan}}^{2}x+8\mathrm{tan}x-3=0$

Hattie Schaeffer

Beginner2022-01-05Added 37 answers

This is a classical linear trigonometric equation

8s=5c+1

Vasquez

Expert2022-01-08Added 669 answers

Rewrite it as

Using the quadratic formula, the roots of

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