what is the derivative of \sec^2 x I'm using the q

Kathy Williams

Kathy Williams

Answered question

2022-01-01

what is the derivative of sec2x
I'm using the quotient rule and so I rewrite sec2x  as  1cos2x
Then set u=1,u=0  then  v=cos2x and v=2sinxcosx
I then get 2sinxcosxcos4x
but when I simplify that I don't get 2sec2xtanx which is the correct answer?

Answer & Explanation

Samantha Brown

Samantha Brown

Beginner2022-01-02Added 35 answers

2sin(x)cos(x)cos4(x)=2sin(x)cos(x)1cos2(x)=2tan(x)sec2(x)
John Koga

John Koga

Beginner2022-01-03Added 33 answers

2sin(x)cos(x)cos2(x)cos2(x)=2sec2(x)tan(x)
Vasquez

Vasquez

Expert2022-01-08Added 669 answers

2sinxcosxcos4x==2(sinx)(cosx)[cos2x]==2tanxsec2x

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