Solving an equation with sin &#x2061;<!-- ⁡ --> ( x ) in the exponent: 2

Kaiden Wilkins

Kaiden Wilkins

Answered question

2022-04-06

Solving an equation with sin ( x ) in the exponent: 2 sin ( x ) cos ( x ) + 1 = 1

Answer & Explanation

odvucimo1pp17

odvucimo1pp17

Beginner2022-04-07Added 23 answers

2 sin x cos x + 1 = 1 2 sin x cos x = 0 2 sin x = 0  or  cos x = 0
Can you deduce the solution from here?
Jaime Coleman

Jaime Coleman

Beginner2022-04-08Added 3 answers

2 sin ( x ) cos ( x ) + 1 = 1 gives 2 sin ( x ) cos ( x ) = 0, so that implies x = π 2 + k π is the only solution, where k is an integer.

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