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Aedan Gonzales

Aedan Gonzales

Answered question

2022-05-07

The equation is
a cos ( ω t ) + b sin ( ω t ) = A cos ( ω t + ϕ )
I must have forgotten how the right hand side follows from the left hand side.
Some hints would be helpful

Answer & Explanation

Taniya Wood

Taniya Wood

Beginner2022-05-08Added 19 answers

Let A = a 2 + b 2 and ϕ be an angle such that cos ϕ = a a 2 + b 2 and sin ϕ = b a 2 + b 2
Then, by using the identity cos ( x + y ) = cos x cos y sin x sin y, we have:
a cos ( ω t ) + b sin ( ω t ) = a 2 + b 2 [ a a 2 + b 2 cos ( ω t ) b a 2 + b 2 sin ( ω t ) ] = A [ cos ϕ cos ( ω t ) sin ϕ sin ( ω t ) ] = A cos ( ω t + ϕ ) .
Hailee Stout

Hailee Stout

Beginner2022-05-09Added 7 answers

Try breaking down A cos ( ω t + ϕ )
A cos ( ω t + ϕ ) = A ( cos ω t cos ϕ sin ω t sin ϕ ) = ( A cos ϕ ) cos ω t ( A sin ϕ ) sin ω t
Try to show that for arbitrary constants a and b that there exists constants A and ϕ such that
a = A cos ϕ
and
b = A sin ϕ
What is a 2 + b 2 ?

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