Best solutions to - "Solve: 4sin⁡(2y−0.3)+5cos⁡(2y−0.3)=0"

glamrockqueen7

Answered question

2020-10-26

Solve:

4 \sin (2 y - 0.3) + 5 \cos (2 y - 0.3) = 0

davonliefI

Skilled2020-10-27Added 79 answers

4 \sin (x) + 5 \cos (x) = 0

4 \sin = - 5 \cos

\sin (x) = (- \frac{5}{4}) \cos i (x)

\sin^{2} = (\frac{25}{16}) \cos^{2} = 1.5625 \cos^{2}

\sin^{2} = 1.5625 \cdot [1 - \sin^{2} (x)]

\sin^{2} (1 + 1.5625) = 1.5625

2.5625 \sin^{2} = 1.5625

\sin^{2} (x) = (\frac{1.5625}{2.5625}) = 0.609756097

\sin (x) = \sqrt{0.609 \dots .} = 0.780868809

invers

\sin x = 51.34019175

deg

2 y - 0.3 = 51.34019175

2 y = 51.34 + 0.3 = 51.64019175

y = \frac{51.640}{2} = 25.82009587

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