1.the length of a rectangle is 3 in. more than the width. if the perimeter is 30 in., find the area of a rectangle.2.a square has an area of 16 y d 2 . what is the perimeterof the square?3.The area of a triangle is 112 m 2 . If the length of thebase is 16 m, what is the height?4.What is the maximum area for a rectangle with a perimeter of 40centimeters?5.The length of a rectangle is 2 in. more than the width. If the perimeter is 24 in., find the area of the rectangle.

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1.the length of a rectangle is 3 in. more than the width. if the perimeter is 30 in., find the area of a rectangle.2.a square has an area of   16  y      d          2      . what is the perimeterof the square?3.The area of a triangle is   112      m          2      . If the length of thebase is 16 m, what is the height?4.What is the maximum area for a rectangle with a perimeter of 40centimeters?5.The length of a rectangle is 2 in. more than the width. If the perimeter is 24 in., find the area of the rectangle.

Alejandra Blackwell · Accepted Answer

1) It is a   6  ×  9 rectangle, so the area is   6  ∗  9  =  54  i      n          2      2) It is a   4  ×  4 square so the perimeter is 16in3) 112/8 = 14 so the height of the triangle is 14m4) The rectangle with the greatest area is a square, so itwould be a   10  ×  10 square with a area of 100cm5) It is a   5  ×  7 rectange, so the area is   5  ∗  7  =  35  i      n          2

wendi1019gt · Accepted Answer

1. let x be witdth3+x=lengthP=2L+2W,2x+2(x+3)=304x+6=30, x=6 inches width3+x=3+6=9 inches length  A  =  l  w  =  9  (  6  )  =  54  i      n          2      2.   A  =      x          2        ,  16  =      x          2        ,  x  =  4  y  dP=4s=4(4)=16yd3. area triangle  A  =      1    2    b  h  ,  112  =      1    2    (  16  )  h224=16h, h=14m4.P=2l+2w,40=2l+2w,l+w=20, l=20-w  A  =  l  w  =  (  20  −  w  )  w  =  20  w  −      w          2      find vertex  w  =  −      b          2      a        =  −      20          −      2        =  10  A  (  10  )  =  20  (  10  )  −      10          2        =  200  −  100  =  100  c      m          2      5. let x be width2+x = lengthp=2l+2w, 24=2(2+x)+2x2x+2x+4=24, 4x=20, x=5 in widthlength 2+x=2+5=7innow area  A  =  7  (  5  )  =  35  i      n          2

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