Solve equations 0 ≤ θ &lt; 2 πa) 4 3 = 6 cos ⁡ θb) − 2 + cos ⁡ θ = − 4 − 2 2 c) − 4 = 4 cos ⁡ θd) − 2 = − 4 sin ⁡ θ

Question

Solve equations   0  ≤  θ  &amp;lt;  2  πa)  4      3    =  6  cos  ⁡  θb)  −  2  +  cos  ⁡  θ  =            −      4      −              2              2  c)  −  4  =  4  cos  ⁡  θd)  −  2  =  −  4  sin  ⁡  θ

wietselau · Accepted Answer

a  )  4      3    =  6  cos  ⁡  θ    cos  ⁡  θ  =            4              3              6    =  1.1547Range of cos theta is [-1,1] it cant be greater than Answer to No solution  b  )  −  2  +  cos  ⁡  θ  =            −      4      −              2              2      cos  ⁡  θ  =            −      4      −              2            +      2      ×      2        2      cos  ⁡  θ  =            −              2              2    ⇒  θ  =      cos          −      1        ⁡  (  −      1          2        )    θ  =            3      π        4    ,            5      π        4    c  )  −  4  =  4  cos  ⁡  θ    cos  ⁡  θ  =  −  1    θ  =      cos          −      1        ⁡  (  −  1  )  =  π    θ  =  π  d  )  ⇒  −  2  =  −  4  sin  ⁡  θ    sin  ⁡  θ  =            −      2              −      4        =      1    2      θ  =      sin          −      1        ⁡  (      1    2    )  =      π    6    ,            5      π        6      θ  =      π    6    ,            5      π        6    e  )  4  =  4  +  tan  ⁡  θ    tan  ⁡  θ  =  4  −  4    tan  ⁡  θ  =  0    θ  =  0  ,  π

Solve equations 0 <= theta <= 2pi a)4sqrt3=6 cos theta b)-2+cos theta=(-4-sqrt2)/(2) c)-4=4 cos theta d)-2=-4 sin theta e)4=4 +tan theta

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