Number of real solution of Trigonometric Equation Number of solution of the equation (sin x+ cos x+2)^(4)=128 sin(2x) AA x in [0,(pi)/(2)]

Adison Rogers

Adison Rogers

Answered question

2022-11-06

Number of real solution of Trigonometric Equation
Number of solution of the equation ( sin x + cos x + 2 ) 4 = 128 sin ( 2 x ) x [ 0 , π 2 ]
What i try
sin x + cos x + 2 = 2 cos ( x π 4 ) + 2
And put x π 4 = t and t [ π 4 , π 4 ]
( cos t + 2 ) 4 = 64 cos ( 2 t )
How do i solve it Help me

Answer & Explanation

Taniyah Lin

Taniyah Lin

Beginner2022-11-07Added 14 answers

From arithmetic Geometric Inequality
sin x + cos x + 2 4 [ sin x cos x ] 1 4
( sin x + cos x + 2 ) 4 128 sin 2 x
Equality hold when sin x = cos x = 1 = 1
Jadon Johnson

Jadon Johnson

Beginner2022-11-08Added 3 answers

Let sin x + cos x = t
Thus, by C-S
| t | ( 1 + 1 ) ( sin 2 x + cos 2 x ) = 2
and we need to solve that f ( t ) = 0 , where
f ( t ) = ( t + 2 ) 4 128 ( t 2 1 ) .
But
f ( t ) = 12 ( t + 2 ) 2 256 12 ( 2 + 2 ) 2 256 < 0 ,
which says that f is a concave function on [ 0 , 2 ] and since f ( 0 ) > 0 and f ( 2 ) > 0,
we see that our equation has no real roots.

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