Solve system of 5 trigonometric equations What is the best way to solve the system of following trigonometric equations with respect to w_l,w_r,b_l,b_r? F_x=w_l^2sin(b_l)+w_r^2sin(b_r) F_z=w_l^2cos(b_l)+w_r^2cos(b_r) M_x=w_r^2cos(b_r)-w_l^2cos(b_l) M_y=w_l^2sin(b_l)+w_r^2sin(b_r) M_z=w_r^2sin(b_r)-w_l^2sin(b_l) I need to find relation between w_l, w_r, b_l, b_r and symbolic coefficients F_x,F_z,M_x,M_y,M_z

Barrett Osborn

Barrett Osborn

Answered question

2022-11-08

Solve system of 5 trigonometric equations
What is the best way to solve the system of following trigonometric equations with respect to w l , w r , b l , b r ?
F x = w l 2 s i n ( b l ) + w r 2 s i n ( b r )
F z = w l 2 c o s ( b l ) + w r 2 c o s ( b r )
M x = w r 2 c o s ( b r ) w l 2 c o s ( b l )
M y = w l 2 s i n ( b l ) + w r 2 s i n ( b r )
M z = w r 2 s i n ( b r ) w l 2 s i n ( b l )
I need to find relation between w l , w r , b l , b r and symbolic coefficients F x , F z , M x , M y , M z .

Answer & Explanation

Eynardfb0

Eynardfb0

Beginner2022-11-09Added 19 answers

Note that
F z + M x = 2 w r 2 cos b r
F x + M z = 2 w r 2 sin b r
thus for b r and w r we have (dividing one equation by another, using sin 2 θ + cos 2 θ = 1:
tan b r = F x + M z F z + M x
4 w r 4 = ( F x + M z ) 2 + ( F z + M x ) 2
Note also that
F z M x = 2 w l 2 cos b l
F x M z = 2 w 1 2 sin b l
thus for b l and w l we have
tan b l = F x M z F z M x
4 w l 4 = ( F x M z ) 2 + ( F z M x ) 2
(As mentioned in the comments by OP, M y turns out to be unused indeed.)
Kale Sampson

Kale Sampson

Beginner2022-11-10Added 6 answers

If you ignore the fourth equation, since F x and M y are identical, then number the remaining equations 1-4:
Take successively the sum of equations 1 and 4,and the difference of 1 and 4.
Call these equations A and B. Do the same operations on equations 2 and 3, call these C and D.
Now dividing B and D gives
tan β l = F x M z F z M x
Squaring and adding the same gives
4 ω l 4 = ( F x M z ) 2 + ( F z M x ) 2
Now do the same set of operations on equations A and C and you're done.

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