Trigonometry equation problem Show that arctan2 = arccos(1/sqrt5). This is the result of solving one trigonometrical equation.

Rosemary Chase

Rosemary Chase

Answered question

2022-11-09

Trigonometry equation problem
Show that
arctan 2 = arccos ( 1 / 5 ) .
This is the result of solving one trigonometrical equation.

Answer & Explanation

Rebecca Benitez

Rebecca Benitez

Beginner2022-11-10Added 20 answers

Draw the triangle. Opposite = 2. Adjacent = 1. Then use the Pythagorean theorem to find the hypotenuse, and recall that cosine = adjacent over hypotenuse.
Howard Nelson

Howard Nelson

Beginner2022-11-11Added 6 answers

Let θ = arctan 2. Then tan θ = 2 and we need to prove that tan θ = tan ( arccos ( 1 / 5 ) ) = 2. One way is to use the identity
tan x = ± 1 cos 2 x 1 ,
which can be derived from the fundamental identity
cos 2 x + sin 2 x = 1.
For x = 1 / 5 we have that
tan ( arccos ( 1 / 5 ) ) = 1 cos 2 ( arccos ( 1 / 5 ) ) 1 (The sign is positive because  0 < arccos ( 1 / 5 ) < π / 2 ) = 1 ( 1 / 5 ) 2 1 = 2.

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