How to find x in some trigonometric equations How to solve these trigonometric equations? tan2x−sin4x=0 and tan2x=sinx I can't do this, please help me! I did this: tan2x=2sinx (sin2x)/(cos2x)=tan x

Aron Heath

Aron Heath

Answered question

2022-11-13

How to find x in some trigonometric equations
How to solve these trigonometric equations?
tan 2 x sin 4 x = 0
and
tan 2 x = sin x
I can't do this, please help me! I did this:
tan 2 x = 2 sin x sin 2 x cos 2 x = tan x

Answer & Explanation

Nigerkamg5

Nigerkamg5

Beginner2022-11-14Added 20 answers

sin 2 x = 2 tan x 1 + tan 2 x
Just to be clear on how to use this substitution:
tan 2 x = sin 4 x = 2 tan 2 x 1 + tan 2 2 x
Then we have tan 2 x = 0 or 1 + tan 2 2 x = 2 and in this case tan 2 x = ± 1
... from which point we are reduced to considering simple cases.
reevelingw97

reevelingw97

Beginner2022-11-15Added 4 answers

Usually, equations with trigonometric functions in them can be solved by substitution using identities. If you know your trigonometric identities really well, then solving these types of equations becomes less difficult. For the first equation, you have
tan 2 x = sin 4 x
In this case, you can use the fact that tan x = sin x cos x to substitute for tan 2 x. Also, there's another identity which states that sin 2 x = 2 sin x cos x, so you can substitute using this identity for sin 4 x. This will give you
sin 2 x cos 2 x = 2 sin 2 x cos 2 x
You should then be able to solve this equation by multiplying through by cos 2 x and using the identity cos 2 x = 1 sin 2 x
Using the identity tan x = sin x cos x and the fact that cos 2 x = 1 sin 2 x, you can manipulate the above to produce
2 sin x cos x 1 sin 2 x 1 sin 2 x = sin x
This simplifies to
sin x 2 ( 2 cos 2 x 2 cos x 1 ) = 0
Then you just have to check to make sure that solutions to the above equation are well-defined in the original equation.

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