Question in a trigonometric equation.I tried it a lot but am not able to get this.Pls help in how should I think when solving this type of question and which side is better to try to simplify first (LHS or RHS).Please share the solution in that way. 1 − sin ⁡ A 1 + sin ⁡ A = 1 + 2 tan ⁡ A ( tan ⁡ A − sec ⁡ A ) One of the ways I tried but am not understand that how to simplify it in such a way that you get the RHS?

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Question in a trigonometric equation.I tried it a lot but am not able to get this.Pls help in how should I think when solving this type of question and which side is better to try to simplify first (LHS or RHS).Please share the solution in that way.            1      −      sin      ⁡      A              1      +      sin      ⁡      A        =  1  +  2  tan  ⁡  A      (    tan    ⁡    A    −    sec    ⁡    A    )  One of the ways I tried but am not understand that how to simplify it in such a way that you get the RHS?

Brooklyn Mcintyre · Accepted Answer

Starting from the LHS we have            1      −      sin      ⁡      (      A      )              1      +      sin      ⁡      (      A      )        =            1      −      sin      ⁡      (      A      )              1      +      sin      ⁡      (      A      )        ⋅            1      −      sin      ⁡      (      A      )              1      −      sin      ⁡      (      A      )        =            1      −      2      sin      ⁡      (      A      )      +              sin        2            ⁡      (      A      )              1      −              sin        2            ⁡      (      A      )        =                    cos        2            ⁡      (      A      )      −      2      sin      ⁡      (      A      )      +      2              sin        2            ⁡      (      A      )                      cos        2            ⁡      (      A      )      using the identity       sin    2    ⁡  (  A  )  +      cos    2    ⁡  (  A  )  =  1. Can you end it now?

Question in a trigonometric equation. (1-sin A)/(1+ sin A) = 1 + 2 tan A (tan A - sec A )

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