A population of values has a normal distribution with and . You intend to draw a random sample of size .
Find the probability that a single randomly selected value is between 119.8 and 121.2.
P(119.8 < X < 121.2)
Find the probability that a sample of size is randomly selected with a mean between 119.8 and 121.2.
P(119.8 < M < 121.2)
Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
(a) Evaluate the standard deviation s for each set of data.
(b) Pool the data to obtain an absolute standard deviation
for the method.
Brämhults Juice, based in Sweden, produces chilled fruit and vegetable juices. A manager at Brämhults is considering purchasing a new machine to bottle 16-fluid-ounce (473-milliliter) bottles of 100% pure carrot juice and wants an estimate of the differ- ence in the mean filling weights between the new machine and the old machine. Random samples of bottles of carrot juice that had been filled by both machines were obtained. Estimate the difference in the mean filling weights between the new and the old machines? Discuss the assumptions. Use a = 0.10.
We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 336 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county.
Let p represent the proportion of the strawberries in a shipment that are bruised.
Young's modulus is a quantitative measure of stiffness of an elastic material. Suppose that for aluminum alloy sheets of a particular type, its mean value and standard deviation are 70 GPa and 1.6 GPa, respectively (values given in the article ''Influence of Material Properties Variability on Springback and Thinning in Sheet Stamping Processes: A Stochastic Analysis'' (Intl. J. of Advanced Manuf. Tech., 2010: 117–134)). If
Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test.
Is
Use technology to find the P-Value.