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Recent questions in College Statistics
College StatisticsOpen question
Bessy KinyaBessy Kinya2022-06-22

 

College StatisticsAnswered question
Manteo2h Manteo2h 2022-06-22

Does accelerating cosmological expansion increase beam spread?
In the standard textbook case, a transmitter of diameter D can produce an electromagnetic beam of wavelength λ that has spread angle θ = 1.22 λ / D. But what happens in an expanding cosmology, especially one that accelerates so that there is an event horizon? Does θ increase with distance?
Obviously each photon will travel along a null geodesic and after conformal time τ have travelled χ = c τ units of co-moving distance. The distance between the beam edges would in flat space be growing as δ = 2 c sin ( θ / 2 ) τ. Now, co-moving coordinates are nice and behave well with conformal time, so I would be mildly confident that this distance is true as measured in co-moving coordinates.
But that means that in proper distance the beam diameter is multiplied by the scale factor, a ( t ) δ (where t is the time corresponding to τ), and hence θ increases. However, the distance to the origin in these coordinates has also increased to a ( t ) ( c t ), so that seems to cancel the expansion - if we measure θ ( t ) globally by dividing the lengths.
But it seems that locally we should see the edges getting separated at an accelerating pace; after all, the local observers will see the emitter accelerating away from them, producing a wider and wider beam near their location since it was emitted further away. From this perspective as time goes by the beam ends up closer and closer to θ = π (and ever more red-shifted, which presumably keeps the total power across it constant).
Does this analysis work, or did I slip on one or more coordinate systems?

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