A company produces millions of 1-pound packages of bacon every week. Company specifications allow for no more than 3 percent of the 1-pound packages to be underweight. To investigate compliance with the specifications, the company’s quality control manager selected a random sample of 1,000 packages produced in one week and found 40 packages, or 4 percent, to be underweight.
Assuming all conditions for inference are met, do the data provide convincing statistical evidence at the significance level of that more than 3 percent of all the packages produced in one week are underweight?
(A) Yes, because the sample estimate of 0.04 is greater than the company specification of 0.03.
(B) Yes, because the p-value of 0.032 is less than the significance level of 0.05.
(C) Yes, because the p-value of 0.064 is greater than the significance level of 0.05.
(D) No, because the p-value of 0.032 is less than the significance level of 0.05.
(E) No, because the p-value of 0.064 is greater than the significance level of 0.05.
The answer is (B) and I was trying to understand why. My calculation was:
But I get a ridiculously high number. I'm confused about how to get the p-value in this case.
A two-sided t-test for a population mean is conducted of the null hypothesis . If a 90 percent t-interval constructed from the same sample data contains the value of 100, which of the following can be concluded about the test at a significance level of ?
(A) The p-value is less than 0.10, and should be rejected.
(B) The p-value is less than 0.10, and should not be rejected.
(C) The p-value is greater than 0.10, and should be rejected.
(D) The p-value is greater than 0.10, and should not be rejected.
(E) There is not enough information given to make a conclusion about the p-value and .
Here the answer is D, but again I am confused. How can I find the p-value in this case?