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Recent questions in Acceleration Due to Gravity

ulcerat9jr 2022-05-02

Getting acceleration due to gravity from dropping ball experiment
This seems like pretty basic experiment, but I'm having a lot of trouble with it. Basically, I have two timer gates that measure time between two signals, and I drop metal ball between them. This way I'm getting distance traveled, and time. Ball is dropped from right above the first gate to make sure initial velocity is as small as possible (no way to make it 0 with this setup/timer). I'm assuming $v$ initial is $0 \frac{m}{s}$ . Gates are $1$ meter apart.
Times are pretty consistent, and average result from dropping ball from $1.0$ meters is $0.4003$ seconds.
So now I have $3$ [constant acceleration] equations that I can use to get $g$
1.
$d_{t r a v e l e d} = v_{i n i t i a l} . t + \frac{1}{2} a t^{2}$
$a = \frac{2 d}{t^{2}}$
$a = \frac{2.1}{(.4003)^{2}}$
$a = 12.48 \frac{m}{s^{2}}$
2.
$v_{f}^{2} = v_{i}^{2} + 2 a d$
$a = \frac{v_{f}^{2} - v_{i}^{2}}{2 d}$
$v_{f} = \frac{d i s t a n c e}{t i m e} = \frac{1.0}{0.4003} = 2.5 \frac{m}{s}$
$a = \frac{(2.5 \frac{m}{s})^{2}}{2.1 m}$
$a = 3.125 \frac{m}{s^{2}}$
3.
$v_{f} = v_{i} + a t$
$a = \frac{v_{f} - v_{i}}{t}$
$a = \frac{2.5 m / s - 0}{0.4003 s}$
$a = 6.25 \frac{m}{s^{2}}$
I'm getting three different results. And all of them are far from $9.8 \frac{m}{s^{2}}$ . No idea what I'm doing wrong.
Also, if I would drop that ball from different heights, and plot distance-time graph, how can I get acceleration from that?

Araceli Soto 2022-04-30

How to calculate acceleration due to gravity in a 3D $N$ -Body system?
How do you calculate acceleration due to gravity for objects in 3D space?
My current understanding for the force due to gravity on object $i$ from object $j$ is
$F_{g} = (r_{j} - r_{i}) m_{j} m_{i} G / | r_{j} - r_{i} |^{3}$
where $r_{i}$ and $r_{j}$ are the 3D position vectors of object $i$ and object $j$
Is this right? If not, what is?
Also, should
$| r_{j} - r_{i} |^{3}$
be the same as $[(x_{j} - x_{i})^{2} + (y_{j} - y_{i})^{2} + (z_{j} - z_{i})^{2}]^{3 / 2}$ or the vector $[| x_{j} - x_{i} |, | y_{j} - y_{i} |, | z_{j} - z_{i} |]$ cubed?

Thaddeus Sanders 2022-04-12

What is the effect of acceleration due to gravity on horizontal acceleration?
The question is the following:
An object accelerates from rest to $100 k m$ per hour in $4.0 seconds$ . What fraction of the acceleration due to gravity is the car's acceleration?
From the question above, I can work out the acceleration (change in velocity over change in time) of the object using the given quantities: initial velocity ( $0 k p h$ ), final velocity ( $100 k p h$ ), and time ( $4.0 s$ ).
But what does gravitational acceleration have to do with this? Is the answer related to friction created by the downward acceleration due to gravity?

llunallenaipg5r 2022-04-12

Effects of spin on neutron star's surface acceleration due to gravity
Could a neutron star have sufficient mass and spin so that the centripetal force acts opposite to gravity to make the effective acceleration due to gravity zero or close to 1g? What would happen to the matter at the surface?

Cesar Mcguire 2022-04-12

Acceleration due to gravity: what's the derivation?
Modelling the Earth as a symmetric, spherical body (and by using the law of gravitation), we come up with the equation
$w = F_{g} = \frac{G m_{E} m}{R_{E}^{2}}$
How do we arrive to the equation to get the acceleration due to gravity at the earth's surface?
$g = \frac{G M_{E}}{R_{E}^{2}}$
Where:
$G = gravitational constant = 6.67 \times 10^{- 11} N$
$M_{E} = mass of Earth = 5.98 \times 10^{24} k g$
$R_{E} = Earth's radius = 6380 k m$
One thing I know of is the fact that we use Newton's second law, but how?

Jamir Melendez 2022-04-12

How to integrate acceleration due to gravity with height?
If I project a body at a very large velocity such that it reaches a height h which is comparable to Earth's radius, then how to derive an equation for 'h' in terms of initial velocity 'u' and other constants.
This is where I ended up with this problem
S = u²/2g
But g is variable with height as h approaches R
So dg = GM/(R+dr)² --- this is where I think I might be wrong
Hence dS = u²(R+dr)²/GM
So how do I go ahead?

Carina Valenzuela 2022-04-12

Gravitational pull vs. acceleration due to gravity
It might seem obvious but i can't imagine how is gravitational pull is different from acceleration due to gravity?

hard12bb30crg 2022-04-07

Why acceleration due to gravity is not reliably defined?
In Sean Carroll's Spacetime Geometry, there is the following line on Page No.50 in 2014th edition:
"The acceleration of a charged particle in an electromagnetic field is uniquely defined with respect to inertial frames.The EEP,on the other hand,implies that gravity is inescapable- there is no such thing as a "gravitationally neutral object" with respect to which we can measure the acceleration due to gravity. It follows that the acceleration due to gravity is not something that can be reliably defined,and therefore is of little use"
But, we do measure acceleration due to gravity of earth and moon. So why acceleration due to gravity is not reliably defined? Does this mean we cannot measure the true value of acceleration due to gravity of any massive object?

Lennie Davis 2021-12-22

To throw a discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discuss after making one complete revolution. The diameter of the circle in which the discus moves is about 1.8 m. If the thrower takes 1.0 s to complete one revolution, starting from rest, what will be the speed of the discus at release?

Jean Blumer 2021-12-20

A550-N physics student stands on a bathroom scale in an elevator that is supported by a cable. The combined mass of student plus elevator is 850 kg. As the elevator starts moving, the scale reads 450 N.
(a) Find the acceleration of the elevator (magnitude and direction).
(b) What is the acceleration if the scale reads 670 N?
(c) If the scale reads zero, should the student worry? Explain.
(d) What is the tension in the cable in parts (a) and (с)?

Bobbie Comstock 2021-12-17

A hot-air balloonist, rising vertically with a constant velocity of magnitude 5.00 m/s, releases a sandbag at an instant when the balloon is 40.0 m above the ground. After the sandbag is released, it is in free fall. (a) Compute the position and velocity of the sandbag at 0.250 s and 1.00 s after its release. (b) How many seconds after its release does the bag strike the ground? (c) With what magnitude of velocity does it strike the ground? (d) What is the greatest height above the ground that the sandbag reaches? (e) Sketch $a_{y} - t, v_{y} t$ , and y-t graphs for the motion.

Cynthia Bell 2021-12-16

A bicycle with 0.80-m-diameter tires is coasting on a level road at 5.6 m/s. A small blue dot has been painted on the tread of the rear tire. a. What is the angular speed of the tires? b. What is the speed of the blue dot when it is 0.80 m above the road? c. What is the speed of the blue dot when it is 0.40 m above the road?

Joseph Krupa 2021-12-14

An antelope moving with constant acceleration covers the distance between two points 70.0 m apart in 6.00 s. Its speed as it passes the second point is 15.0 m/s. What are (a) its speed at the first point and (b) its acceleration?

Walter Clyburn 2021-12-10

A fan blade rotates with angular velocity given by $ω_{z} (t) = γ - β t^{2}$ , where $γ = 5.00 r a \frac{d}{s}$ and $β = 0.800 r a \frac{d}{s^{3}}$ . (a) Calculate the angular acceleration as a function of time. (b) Calculate the instantaneous angular acceleration $a_{z}$ at $t = 3.00 s$ at t = 3.00 s and the average angular acceleration $a_{a v - z}$ for the time interval t = 0 to t = 3.00 s. How do these two quantities compare? If they are different, why?

smellmovinglz 2021-11-23

The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth.
(a) Compute the acceleration due to gravity on the surface of Venus from these data.
(b) If a rock weighs 75.0 N on earth, what would it weigh at the surface of Venuse?

Ballestin3a 2021-11-21

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the player accelerates uniformly, determine the distance he runs.

Michael Dennis 2021-11-21

A jet plane lands with a speed of 100 m/s and can accelerate at a maximum rate of $- 5.00 \frac{m}{s^{2}}$ as it comes to rest. Can this plane land on a small tropical island airport where the runway is 0.800 km long?

Tepliwodav0 2021-11-21

It takes the elevator in a skyscraper 4.0 s to reach its cruising speed of 10 m/s. A 60 kg passenger gets aboard on the ground floor. What is the passengers

Serotoninl7 2021-11-18

A horizontal rope is tied to a 50 kg box on frictionless ice. What is the tension in the rope if a. The box is at rest? b. The box moves at a steady 5.0 m/s? c. The box has $v_{x} = 5.0 \frac{m}{s}$ and $a_{x} = 5.0 \frac{m}{s^{2}} ?$

sklicatias 2021-11-18

A rocket starts from rest and moves upward from the surface of the earth. For the first 10.0 s of its motion, the vertical acceleration of the rocket is given by $a_{y} = 12.80 \frac{m}{s^{3}}$ )t, where the + y-direction is upward. (a) What is the height of the rocket above the surface of the earth at t = 10.0 s? (b) What is the speed of the rocket when it is 325 m above the surface of the earth?

If you need to calculate acceleration due to gravity, start with the examples of equations to learn how much information must be provided as you describe the experiment. The majority of answers that are presented below address this aspect of things. You may also check relevant acceleration due to gravity problems that are experimental in their nature. Both of them can be helpful as you learn how to apply equations or offer verbal explanations. Regardless if you are in Grade 9 at school or need to calculate something as an Astroengineer, we have the answers that will satisfy your needs.

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