Let it be a tetrahedron with the numbers 1,2,3 and 4 on its faces.The tetrahedron is launch 3 times. Each time, the number that stays face down is registered.
1 )In total how many possible ways there are to registered the 3 launches?
As there are 4 numbers to 3 launches(positions), the order matters and each number can repeats itself. I used a permutation with replacement:
3 )How many possible ways there are to the number 1 appears only 1 time face down?
There are 3 ways for number 1 can be put on the 3 launches. For the 2 left there is {2,3,4}.So I made a permutation with replacement:
4)How many possible ways there are to the number 1 appears exactly 2 times face down?
First I made a combination: C(3,2) to find the number of ways that the pair of 1's can be put in the 3 launchs.Then I multiplied by 3, that is {2,3,4} :
Is this correct?