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Precalculus
Values of x satisfying sinx⋅cos3x>sin3x⋅cosx My Attempt sinxcosx⋅(cos2x−sin2x)=12⋅sin2x⋅cos2x=14⋅sin4x>0⟹sin4x>0x∈(0,π)⟹4x∈(0,4π) 4x∈(0,π)∪(2π,3π)⇒x∈(0,π4)∪(π2,3π4) But, my reference gives the solution, x∈(0,π4)∪(3π4,π) where am I going wrong with my attempt?